Integrand size = 28, antiderivative size = 245 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=\frac {\left (b^2 d-a b e+a^2 f\right ) x^2}{2 b^3}+\frac {(b e-a f) x^5}{5 b^2}+\frac {f x^8}{8 b}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} \sqrt [3]{a} b^{11/3}}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 \sqrt [3]{a} b^{11/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 \sqrt [3]{a} b^{11/3}} \]
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Time = 0.15 (sec) , antiderivative size = 245, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {1850, 1502, 298, 31, 648, 631, 210, 642} \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=\frac {x^2 \left (a^2 f-a b e+b^2 d\right )}{2 b^3}-\frac {\arctan \left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right ) \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{\sqrt {3} \sqrt [3]{a} b^{11/3}}-\frac {\log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{3 \sqrt [3]{a} b^{11/3}}+\frac {\log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right ) \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{6 \sqrt [3]{a} b^{11/3}}+\frac {x^5 (b e-a f)}{5 b^2}+\frac {f x^8}{8 b} \]
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Rule 31
Rule 210
Rule 298
Rule 631
Rule 642
Rule 648
Rule 1502
Rule 1850
Rubi steps \begin{align*} \text {integral}& = \frac {f x^8}{8 b}+\frac {\int \frac {x \left (8 b c+8 b d x^3+8 (b e-a f) x^6\right )}{a+b x^3} \, dx}{8 b} \\ & = \frac {f x^8}{8 b}+\frac {\int \left (\frac {8 \left (b^2 d-a b e+a^2 f\right ) x}{b^2}+\frac {8 (b e-a f) x^4}{b}+\frac {8 \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) x}{b^2 \left (a+b x^3\right )}\right ) \, dx}{8 b} \\ & = \frac {\left (b^2 d-a b e+a^2 f\right ) x^2}{2 b^3}+\frac {(b e-a f) x^5}{5 b^2}+\frac {f x^8}{8 b}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \int \frac {x}{a+b x^3} \, dx}{b^3} \\ & = \frac {\left (b^2 d-a b e+a^2 f\right ) x^2}{2 b^3}+\frac {(b e-a f) x^5}{5 b^2}+\frac {f x^8}{8 b}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \int \frac {1}{\sqrt [3]{a}+\sqrt [3]{b} x} \, dx}{3 \sqrt [3]{a} b^{10/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \int \frac {\sqrt [3]{a}+\sqrt [3]{b} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{3 \sqrt [3]{a} b^{10/3}} \\ & = \frac {\left (b^2 d-a b e+a^2 f\right ) x^2}{2 b^3}+\frac {(b e-a f) x^5}{5 b^2}+\frac {f x^8}{8 b}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 \sqrt [3]{a} b^{11/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \int \frac {-\sqrt [3]{a} \sqrt [3]{b}+2 b^{2/3} x}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{6 \sqrt [3]{a} b^{11/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \int \frac {1}{a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2} \, dx}{2 b^{10/3}} \\ & = \frac {\left (b^2 d-a b e+a^2 f\right ) x^2}{2 b^3}+\frac {(b e-a f) x^5}{5 b^2}+\frac {f x^8}{8 b}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 \sqrt [3]{a} b^{11/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 \sqrt [3]{a} b^{11/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}\right )}{\sqrt [3]{a} b^{11/3}} \\ & = \frac {\left (b^2 d-a b e+a^2 f\right ) x^2}{2 b^3}+\frac {(b e-a f) x^5}{5 b^2}+\frac {f x^8}{8 b}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \tan ^{-1}\left (\frac {\sqrt [3]{a}-2 \sqrt [3]{b} x}{\sqrt {3} \sqrt [3]{a}}\right )}{\sqrt {3} \sqrt [3]{a} b^{11/3}}-\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{3 \sqrt [3]{a} b^{11/3}}+\frac {\left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{6 \sqrt [3]{a} b^{11/3}} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 231, normalized size of antiderivative = 0.94 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=\frac {60 b^{2/3} \left (b^2 d-a b e+a^2 f\right ) x^2+24 b^{5/3} (b e-a f) x^5+15 b^{8/3} f x^8+\frac {40 \sqrt {3} \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right ) \arctan \left (\frac {1-\frac {2 \sqrt [3]{b} x}{\sqrt [3]{a}}}{\sqrt {3}}\right )}{\sqrt [3]{a}}+\frac {40 \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right ) \log \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\sqrt [3]{a}}+\frac {20 \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right ) \log \left (a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2\right )}{\sqrt [3]{a}}}{120 b^{11/3}} \]
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Result contains higher order function than in optimal. Order 9 vs. order 3.
Time = 1.52 (sec) , antiderivative size = 112, normalized size of antiderivative = 0.46
method | result | size |
risch | \(\frac {f \,x^{8}}{8 b}-\frac {x^{5} a f}{5 b^{2}}+\frac {x^{5} e}{5 b}+\frac {a^{2} f \,x^{2}}{2 b^{3}}-\frac {a e \,x^{2}}{2 b^{2}}+\frac {d \,x^{2}}{2 b}+\frac {\munderset {\textit {\_R} =\operatorname {RootOf}\left (b \,\textit {\_Z}^{3}+a \right )}{\sum }\frac {\left (-f \,a^{3}+a^{2} b e -a \,b^{2} d +b^{3} c \right ) \ln \left (x -\textit {\_R} \right )}{\textit {\_R}}}{3 b^{4}}\) | \(112\) |
default | \(\frac {\frac {b^{2} f \,x^{8}}{8}+\frac {\left (-a f b +b^{2} e \right ) x^{5}}{5}+\frac {\left (a^{2} f -a e b +b^{2} d \right ) x^{2}}{2}}{b^{3}}-\frac {\left (-\frac {\ln \left (x +\left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 b \left (\frac {a}{b}\right )^{\frac {1}{3}}}+\frac {\ln \left (x^{2}-\left (\frac {a}{b}\right )^{\frac {1}{3}} x +\left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 b \left (\frac {a}{b}\right )^{\frac {1}{3}}}+\frac {\sqrt {3}\, \arctan \left (\frac {\sqrt {3}\, \left (\frac {2 x}{\left (\frac {a}{b}\right )^{\frac {1}{3}}}-1\right )}{3}\right )}{3 b \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right ) \left (f \,a^{3}-a^{2} b e +a \,b^{2} d -b^{3} c \right )}{b^{3}}\) | \(173\) |
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Time = 0.31 (sec) , antiderivative size = 568, normalized size of antiderivative = 2.32 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=\left [\frac {15 \, a b^{4} f x^{8} + 24 \, {\left (a b^{4} e - a^{2} b^{3} f\right )} x^{5} + 60 \, {\left (a b^{4} d - a^{2} b^{3} e + a^{3} b^{2} f\right )} x^{2} - 60 \, \sqrt {\frac {1}{3}} {\left (a b^{4} c - a^{2} b^{3} d + a^{3} b^{2} e - a^{4} b f\right )} \sqrt {-\frac {\left (a b^{2}\right )^{\frac {1}{3}}}{a}} \log \left (\frac {2 \, b^{2} x^{3} - a b - 3 \, \sqrt {\frac {1}{3}} {\left (a b x + 2 \, \left (a b^{2}\right )^{\frac {2}{3}} x^{2} - \left (a b^{2}\right )^{\frac {1}{3}} a\right )} \sqrt {-\frac {\left (a b^{2}\right )^{\frac {1}{3}}}{a}} - 3 \, \left (a b^{2}\right )^{\frac {2}{3}} x}{b x^{3} + a}\right ) + 20 \, {\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \left (a b^{2}\right )^{\frac {2}{3}} \log \left (b^{2} x^{2} - \left (a b^{2}\right )^{\frac {1}{3}} b x + \left (a b^{2}\right )^{\frac {2}{3}}\right ) - 40 \, {\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \left (a b^{2}\right )^{\frac {2}{3}} \log \left (b x + \left (a b^{2}\right )^{\frac {1}{3}}\right )}{120 \, a b^{5}}, \frac {15 \, a b^{4} f x^{8} + 24 \, {\left (a b^{4} e - a^{2} b^{3} f\right )} x^{5} + 60 \, {\left (a b^{4} d - a^{2} b^{3} e + a^{3} b^{2} f\right )} x^{2} - 120 \, \sqrt {\frac {1}{3}} {\left (a b^{4} c - a^{2} b^{3} d + a^{3} b^{2} e - a^{4} b f\right )} \sqrt {\frac {\left (a b^{2}\right )^{\frac {1}{3}}}{a}} \arctan \left (-\frac {\sqrt {\frac {1}{3}} {\left (2 \, b x - \left (a b^{2}\right )^{\frac {1}{3}}\right )} \sqrt {\frac {\left (a b^{2}\right )^{\frac {1}{3}}}{a}}}{b}\right ) + 20 \, {\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \left (a b^{2}\right )^{\frac {2}{3}} \log \left (b^{2} x^{2} - \left (a b^{2}\right )^{\frac {1}{3}} b x + \left (a b^{2}\right )^{\frac {2}{3}}\right ) - 40 \, {\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \left (a b^{2}\right )^{\frac {2}{3}} \log \left (b x + \left (a b^{2}\right )^{\frac {1}{3}}\right )}{120 \, a b^{5}}\right ] \]
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Time = 0.77 (sec) , antiderivative size = 427, normalized size of antiderivative = 1.74 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=x^{5} \left (- \frac {a f}{5 b^{2}} + \frac {e}{5 b}\right ) + x^{2} \left (\frac {a^{2} f}{2 b^{3}} - \frac {a e}{2 b^{2}} + \frac {d}{2 b}\right ) + \operatorname {RootSum} {\left (27 t^{3} a b^{11} - a^{9} f^{3} + 3 a^{8} b e f^{2} - 3 a^{7} b^{2} d f^{2} - 3 a^{7} b^{2} e^{2} f + 3 a^{6} b^{3} c f^{2} + 6 a^{6} b^{3} d e f + a^{6} b^{3} e^{3} - 6 a^{5} b^{4} c e f - 3 a^{5} b^{4} d^{2} f - 3 a^{5} b^{4} d e^{2} + 6 a^{4} b^{5} c d f + 3 a^{4} b^{5} c e^{2} + 3 a^{4} b^{5} d^{2} e - 3 a^{3} b^{6} c^{2} f - 6 a^{3} b^{6} c d e - a^{3} b^{6} d^{3} + 3 a^{2} b^{7} c^{2} e + 3 a^{2} b^{7} c d^{2} - 3 a b^{8} c^{2} d + b^{9} c^{3}, \left ( t \mapsto t \log {\left (\frac {9 t^{2} a b^{7}}{a^{6} f^{2} - 2 a^{5} b e f + 2 a^{4} b^{2} d f + a^{4} b^{2} e^{2} - 2 a^{3} b^{3} c f - 2 a^{3} b^{3} d e + 2 a^{2} b^{4} c e + a^{2} b^{4} d^{2} - 2 a b^{5} c d + b^{6} c^{2}} + x \right )} \right )\right )} + \frac {f x^{8}}{8 b} \]
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Time = 0.30 (sec) , antiderivative size = 225, normalized size of antiderivative = 0.92 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=\frac {\sqrt {3} {\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \arctan \left (\frac {\sqrt {3} {\left (2 \, x - \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{3 \, b^{4} \left (\frac {a}{b}\right )^{\frac {1}{3}}} + \frac {5 \, b^{2} f x^{8} + 8 \, {\left (b^{2} e - a b f\right )} x^{5} + 20 \, {\left (b^{2} d - a b e + a^{2} f\right )} x^{2}}{40 \, b^{3}} + \frac {{\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \log \left (x^{2} - x \left (\frac {a}{b}\right )^{\frac {1}{3}} + \left (\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 \, b^{4} \left (\frac {a}{b}\right )^{\frac {1}{3}}} - \frac {{\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \log \left (x + \left (\frac {a}{b}\right )^{\frac {1}{3}}\right )}{3 \, b^{4} \left (\frac {a}{b}\right )^{\frac {1}{3}}} \]
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Time = 0.28 (sec) , antiderivative size = 286, normalized size of antiderivative = 1.17 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=\frac {\sqrt {3} {\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \arctan \left (\frac {\sqrt {3} {\left (2 \, x + \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )}}{3 \, \left (-\frac {a}{b}\right )^{\frac {1}{3}}}\right )}{3 \, \left (-a b^{2}\right )^{\frac {1}{3}} b^{3}} - \frac {{\left (b^{3} c - a b^{2} d + a^{2} b e - a^{3} f\right )} \log \left (x^{2} + x \left (-\frac {a}{b}\right )^{\frac {1}{3}} + \left (-\frac {a}{b}\right )^{\frac {2}{3}}\right )}{6 \, \left (-a b^{2}\right )^{\frac {1}{3}} b^{3}} - \frac {{\left (b^{8} c \left (-\frac {a}{b}\right )^{\frac {1}{3}} - a b^{7} d \left (-\frac {a}{b}\right )^{\frac {1}{3}} + a^{2} b^{6} e \left (-\frac {a}{b}\right )^{\frac {1}{3}} - a^{3} b^{5} f \left (-\frac {a}{b}\right )^{\frac {1}{3}}\right )} \left (-\frac {a}{b}\right )^{\frac {1}{3}} \log \left ({\left | x - \left (-\frac {a}{b}\right )^{\frac {1}{3}} \right |}\right )}{3 \, a b^{8}} + \frac {5 \, b^{7} f x^{8} + 8 \, b^{7} e x^{5} - 8 \, a b^{6} f x^{5} + 20 \, b^{7} d x^{2} - 20 \, a b^{6} e x^{2} + 20 \, a^{2} b^{5} f x^{2}}{40 \, b^{8}} \]
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Time = 9.76 (sec) , antiderivative size = 225, normalized size of antiderivative = 0.92 \[ \int \frac {x \left (c+d x^3+e x^6+f x^9\right )}{a+b x^3} \, dx=x^5\,\left (\frac {e}{5\,b}-\frac {a\,f}{5\,b^2}\right )+x^2\,\left (\frac {d}{2\,b}-\frac {a\,\left (\frac {e}{b}-\frac {a\,f}{b^2}\right )}{2\,b}\right )+\frac {f\,x^8}{8\,b}-\frac {\ln \left (b^{1/3}\,x+a^{1/3}\right )\,\left (-f\,a^3+e\,a^2\,b-d\,a\,b^2+c\,b^3\right )}{3\,a^{1/3}\,b^{11/3}}+\frac {\ln \left (2\,b^{1/3}\,x-a^{1/3}+\sqrt {3}\,a^{1/3}\,1{}\mathrm {i}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (-f\,a^3+e\,a^2\,b-d\,a\,b^2+c\,b^3\right )}{3\,a^{1/3}\,b^{11/3}}-\frac {\ln \left (a^{1/3}-2\,b^{1/3}\,x+\sqrt {3}\,a^{1/3}\,1{}\mathrm {i}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (-f\,a^3+e\,a^2\,b-d\,a\,b^2+c\,b^3\right )}{3\,a^{1/3}\,b^{11/3}} \]
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